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If a1 a2 a3 are in ap such that a1+a7+a16 40

WebCorrect option is B) Given equation can be written as a 1+(a 1+3d)+(a 1+6d)+....+a 1+15d=147 ⇒6a 1+3d(1+2+..+5)=147 ⇒2a 1+15d=49 Now, a 1+a 6+a 11+a 16=4a … Web12 apr. 2024 · PDF The task of collaborative human pose forecasting stands for predicting the future poses of multiple interacting people, given those in previous... Find, read and cite all the research you ...

Let a1,a2,a3,.. be terms of an A.P. If a1+a2+...+ap/a1+a2

Web5 apr. 2024 · Read 04.05.23 - Volume 1, Issue 19 by MHDcurrent on Issuu and browse thousands of other publications on our platform. Start here! Web1 jul. 2024 · Best answer Correct option (D) 900 Explanation: a1 + a5 + a10 + a15 + a20 + a24 = 225 ⇒ 3 (a1 + a24) = 225 (sum of terms equidistant from beginning and end are equal) a1 + a24 = 75 Now a1 + a2 + ........ + a23 + a24 = 24/2 [a1 + a24] = 12 × 75 = 900 ← Prev Question Next Question → Find MCQs & Mock Test JEE Main 2024 Test Series … hawkes pronunciation https://solrealest.com

If a1, a2, a3, .... are in A.P. such that a4a7 = 32 , then the 13^th of ...

Web31 jul. 2024 · Three positive integers a1,a2,a3 are in AP such that a1+a2+a3=33 and a1*a2*a3=1155.Find the integers a1,a2,a3. Advertisement Loved by our community 69 people found it helpful Saisurya Given three positive integers a1, a2,a3, in AP a1*a2*a3*=1155\ => a1+a2+a3=33..............................eq1 according to AP 2 [a2]=a1+a3 … Web20 dec. 2024 · Step-by-step explanation: a1+a7+a16= (a)+ (a+6d)+ (a+15d)=40. 3a+21d=40. a+7d= (40/3) Sum of first 15 terms. =15* (2a+14d)/2. =15* (a+7d) =15* … Web12 apr. 2024 · The nth term in AP series is given by the formula below: T n = a + (n – 1)d Where, n = Number of terms a = First term d = Common difference Now, the condition given becomes, ⇒ a 1 + (a 1 + 6d) + (a 1 + 15d) = 40 ⇒ 3a 1 + 21d = 40 ---- (1) Now, the sum of the first 15 terms is given as: The sum of the n terms is given by the formula: boston bicycle

If a1, a2, a3, … are in A.P. such that a1 + a7 + a16 = 40

Category:Three positive integers a1,a2,a3 are in AP such that a1+a2+a3=33 and a1 ...

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If a1 a2 a3 are in ap such that a1+a7+a16 40

if a1,a2,a3, a4001 are terms of an AP such that 1/a1a2 +1

WebClick here👆to get an answer to your question ️ If a1, a2, a3, .... are in A.P. such that a4a7 = 32 , then the 13^th of the A.P. is Web14 jul. 2024 · Best answer Given : a4/a7 = 2/3 To find : a6 a8 a 6 a 8 We know, an = a + (n – 1)d Where a is a first term or a1 and d is the common difference and n is any natural number When n = 4 : ∴ a4 = a + (4 – 1)d ⇒ a4 = a + 3d When n = 6 : ∴ a6 = a + (6 – 1)d ⇒ a6 = a + 5d When n = 7 : ∴ a7 = a + (7 – 1)d ⇒ a7 = a + 6d When n = 8 : ∴ a8 = a + (8 – 1)d

If a1 a2 a3 are in ap such that a1+a7+a16 40

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Web12 apr. 2024 · The nth term in AP series is given by the formula below: T n = a + (n – 1)d Where, n = Number of terms a = First term d = Common difference Now, the condition … WebCorrect option is B) Given equation can be written as a 1+(a 1+3d)+(a 1+6d)+....+a 1+15d=147 ⇒6a 1+3d(1+2+..+5)=147 ⇒2a 1+15d=49 Now, a 1+a 6+a 11+a 16=4a 1+5d+10d+15d =4a 1+30d=2(2a 1+15d)=2×49 =98 ∴ Option B is correct. Was this answer helpful? 0 0 Similar questions

Web20 mei 2024 · If a1, a2, a3 are positive numbers forming G.P. such that a5 + a7 = 12 and a4.a6 = 9, then a1a9 + a2a8 + a5 + a7 is equal to asked Feb 1 in Mathematics by … WebA1,A2,A3,....is in AP the write in common terms of a and d. .i.e. A1 = a A2 =a+d A3 =a+2d . . A24 = a+23d summing all we get, 4 (6a+69d) = > 4*225 = 900 perhaps. krunal 52 Points 6 years ago u can also solve in such way, (A1+A24) + (A5+A20) + (A10+A15)=225. THEREFORE 3 (A1+A24)=225 (A1+A24)=75. NOW SUM=24/12 (A1+A24) =900

WebIf 1 a1a2+ 1 a2a3 +⋯+ 1 a4000a4001 =10 and a2+a4000= 50, then A a1a4001 =400 B a1a4001 =401 C a1−a4001 =40 D a1−a4001 =30 Solution The correct options are A … WebCorrect option is C) It is given that a 1,a 2,a 3,.......,a n are in A.P and we know that: T he general form of an Arithmetic Progression is a,a+d,a+2d,a+3d and so on. Thus n th term …

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WebClick here👆to get an answer to your question ️ Let a1, a2, a3, .... be terms of an A.P.If a1 + a2 + .... + apa1 + a2 + ..... + aq = p^2q^2, ... are in A.P. such that a 1 ... Find a Value of … hawkes property groupWeb24 feb. 2024 · The nth term in AP series is given by the formula below: T n = a + (n – 1)d Where, n = Number of terms a = First term d = Common difference Now, the condition given becomes, ⇒ a 1 + (a 1 + 6d) + (a 1 + 15d) = 40 ⇒ 3a 1 + 21d = 40 ---- (1) Now, the sum of the first 15 terms is given as: The sum of the n terms is given by the formula: hawkes property group londonWeb18 nov. 2014 · if a1,a2,a3, a4001 are terms of an AP such that 1/a1a2 +1/a2a3+ +1/a4000a4001 = 10 and a2+a4000=50, then a1-a4001 is equal to (A)20 (B)30 (C)40 (D) none of ... +1/a4000a4001 = 10 and a2+a4000=50, then a1-a4001 is equal to (A)20 (B)30 (C)40 (D) none of these. Share with your friends. Share 14. We know that, ... hawkes racing stableWebSolution The correct option is C 11 41 Step 1: Determine the common difference d An arithmetic progression (AP) is a progression in which the difference between two consecutive terms is constant. Sum of n terms of AP, is given by S n = n 2 2 a 1 + n - 1 d where a 1 = first term, d = common difference. hawkes publishingWebIf A1, A2, A3, .... an Are in A.P. with Common Difference D, Then the Sum of the Series Sin D [Cosec A1 Cosec A2 + Cosec A1 Cosec A3 + .... + Cosec an − 1 Cosec An] is - Mathematics Shaalaa.com Department of Pre-University Education, Karnataka PUC Karnataka Science Class 11 Textbook Solutions 11069 Important Solutions 5 hawkes racing syndicationsWeb13 okt. 2024 · 0:00 / 7:21 a1,a2,a3...,an are in A.P. such that a1 + a3 + a5 = -12 and a1a2a3=8 then: 2,308 views Oct 13, 2024 10 Dislike Share Save Doubtnut 2.1M subscribers Subscribe To ask... hawkes racing stablesWebIf a1, a2, a3,........ are terms of AP such that a1 + a5 + a10 + a15 + a20 + a24 = 225 , then the sum of first 24 terms is Class 11 >> Applied Mathematics >> Sequences and series >> Arithmetic progression >> If a1, a2, a3,........ are terms of AP s Question hawkes racing melbourne