WebThe standard form of a polynomial in x is a n x n + a n-1 x n-1 +….. + a 1 x + a 0, where a n, a n-1, ….. , a 1, a 0 are constants, a n ≠0 and n is a whole number. For example, algebraic expressions such as √x + x + 5, x 2 + 1/x 2 are not polynomials because all exponents of x in terms of the expressions are not whole numbers. Contents ... Web29 Dec 2024 · The roots of the quadratic equation y2 + 4y + 4 = 0 are: Q2. The roots of the quadratic equation y2 - 13y + 42 = 0 are: Q3. If (4x - y) is a multiple of 3 then 4x2 + 7xy - 2y2 is divisible by Q4. If α, β be the roots of x2 + px + 1 = 0 and γ, δ be the roots of x2 + qx + 1 = 0, then the value of (α − γ) (β − γ) (α + δ) (β + δ) is Q5.

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WebThe first way to approach this is to see if you can factor out something in first two terms and second two terms and get another common factor. So p(x)= x^2 (2x + 5) - 1 (2x+5) works … Weba. Find a quadratic polynomial each with the given numbers as the sum and product of its zeroes are √2, 1/3 respectively. b. Divide the polynomial p(x) by the polynomial g(x) and find the quotient and remainder p(x) =x4–5x+6, g(x) = 2–x2 c. verify the relationship between the zeroes and the coefficients if p(x)=x2+7x+10 d. shareef atlanta hawks

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Web17 Jun 2024 · Best answer 4x2 ˗ 4x + 1 = 0 ⇒ (2x)2 ˗ 2 (2x) (1) + (1)2 = 0 ⇒ (2x ˗ 1)2 = 0 [∵ a2 – 2ab + b2 = (a–b)2] ⇒ (2x ˗ 1)2 = 0 ⇒ x = 1 2 1 2 or x = 1 2 1 2 Sum of zeroes = 1 2 1 2 + 1 2 1 2 = 1 = 1 1 1 1 = −(coef f icient of x) (coef f icient of x2) − ( c o e f f i c i e n t o f x) ( c o e f f i c i e n t o f x 2) WebThe zeroes are a and b. Let us denote the sum and product of the zeroes by S and P respectively. S= a+b and P= ab. Next, we note that the polynomial can be written (by … Web26 Sep 2024 · Q.3: Compute the zeroes of the polynomial 4x2 – 4x – 8. Also, establish a relationship between the zeroes and coefficients. Solution: Let the given polynomial be p (x) = 4x 2 – 4x – 8 To find the zeroes, take p (x) = 0 Now, factorise the equation 4x 2 – 4x – 8 = 0 4x 2 – 4x – 8 = 0 4 (x 2 – x – 2) = 0 x 2 – x – 2 = 0 x 2 – 2x + x – 2 = 0 shareef and co